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0.333x^2+3x-4=-4
We move all terms to the left:
0.333x^2+3x-4-(-4)=0
We add all the numbers together, and all the variables
0.333x^2+3x=0
a = 0.333; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·0.333·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*0.333}=\frac{-6}{0.666} =-9+0.0059999999999993/0.666 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*0.333}=\frac{0}{0.666} =0 $
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